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A ladder rests against a vertical wall a...

A ladder rests against a vertical wall at angle `alpha` to the horizontal . If is foot is pulled away from the wall through a distance 'a' so that it slides a distance 'b' down the wall making the angle `beta` with the horizontal , then a =

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A ladder rests against a wall at an angle alpha to the horizontal. Its foot is pulled away from the wall through a distance 'a' so that it slides a distance 'b' down the wall making an angle beta with the horizontal. Show that: a=b tan(1/2(α+β)) .

A ladder rests against wall at an angle alpha to the harizontal. Its foot is pulled away from the wall through a distance 'a' so that it slides a distance 'b' down the wall making an angle beta with the horzontal, then tan((alpha+beta)/2) =

A ladder rests against a wall at an angle alpha to the horizontal, its foot is pulled away from the wall through a distance a, so that it slides a distance b down the wall making an angle beta with the horizontal. Show that a = b tan 1/2(alpha + beta) .

A ladder rests against a wall making an angle alpha with the horizontal. The foot of the ladder is pulled away from the wall through a distance ‘a’ so that it slides a distance ‘b’ down the wall making an angle beta with the horizontal then the value of (a)/(b) is

ladder rests against a wall at an angle alpha to the horizontal its foot pulled away from the wall through a distance a so that it slides a distance b down the wall making an angle beta with the horizontal.Show that (a)/(b)=(cos alpha-cos beta)/(sin beta-sin alpha)

A ladder rests against a wall making an angle alpha with the horizontal. The foot of the ladder is pulled away from the wall through a distance x, so that it slids a distance y down the wall making an angle beta with the horizontal. Then prove that x = y tan ((alpha + beta)/(2)) .

A ladder rests against a wall making an angle alpha with the horizontal. The foot of the ladder is pulled away from the wall through a distance x so that it slides a distance y down the wall making an angle beta with the horizontal.The correct relation is (A) x=y tan(alpha+beta)/(2) (B) y=x tan(alpha+beta)/(2) (C) x=y tan(alpha+beta) (D) y=x tan(alpha+beta) (in)