Arrange the following carbonions in order of their decreasing stability
`A:H_3C-C-=overset(Theta)C:,B:H-C-=overset(Theta)C:,C:H_3C-overset(Theta)overset(..)(CH_2)`

Decreasing order of stability of the given carbanions is (a) CH_3-C-=overset(Theta)C: (b) H-C-=overset(Theta)C: (c )CH_3-overset(Theta)overset(..)CH_2

Arrange the following in correct order of their stability ? (I) CH-=overset(Theta)C " "(II) CH_(2)=overset(Theta)CH " "(III) CH_(3)-overset(Theta)CH_(2)

Arrange the following anions in increasing order of stability and give reasons: CH_(2)=overset(Theta)(C)H,CH_(3)overset(Theta)(C)H_(2),CH-=overset(Theta)(C)

Arrange in order of increasing stability : overset(-)(C)H_3,(CH_3)_2overset(-)(C)H,(CH_3)_3overset(-)C,CH_3overset(-)(C)H_2

Arrange the following anions in decreasing order of stability : H-overset(O)overset(||)C-underset((P))overset(Ɵ)CH-overset(O)overset(||)C-H CH_(3)-overset(O)overset(||)C-underset((Q))overset(Ɵ)CH-overset(O)overset(||)C-H CH_(3)-overset(O)overset(||)C-overset(Ɵ)CHunderset((R))-overset(O)overset(||)C-underset(* *)overset(* *)O-CH_(3)

Arraange the follwooing carbanions in decreasing order of their stability : I. CH -= overset( -)(C ) II. CH_(3) - C -= overset( - ) ( C ) III. CH_(2) = overset(- )( C ) H IV. CH_(3) - overset( - )( C ) H_(2) The correct choice is :

Arraange the follwooing carbanions in decreasing order of their stability : I. CH -= overset( -)(C ) II. CH_(3) - C -= overset( - ) ( C ) III. CH_(2) = overset(- )( C ) H IV. CH_(3) - overset( - )( C ) H_(2) The correct choice is :

Arrange the following radicals in decreasing order of their stability. (I) overset(*)(C)H_(3) (II) CH_(3)-overset(*)(C )H_(2) (III)