योगफल निकालें
`1^(2)-2^(2)+3^(2)-4^(2)+...16` पदों तक।

(16^(-1)xx5^(3))/(2^(-4))

The circle (x - 1)^(2) + (y-2)^(2) = 16 and (x + 4)^(2) + (y + 3)^(2) =1:

16. "4^(x)-3^(x-(1)/(2))=3^(x+(1)/(2))-2^(2x-1).

(16*2^(n+1)-4*2^(n))/(16*2^(n+2)-2*2^(n+2))

If A= 1/(1xx2)+1/(1xx4)+1/(2xx3)+1/(4xx7)+ 1/(3xx4)+1/(7xx10) ...... upto 20 terms, then what is the value of A? यदि 1/(1xx2)+1/(1xx4)+1/(2xx3)+1/(4xx7)+ 1/(3xx4)+1/(7xx10).....20 पदों तक हो, तो A का मान क्या है?

The value of 8^(2//3)-16^(1//4)-9^(1//2) is

Find : (16a^(2)-2a-3)/(8a^(2)+11a+3) div (3a^(2)-2a-1)/(3a^(2)-11a-4)

1+(4)/(1!)+(16)/(2!)+(64)/(3!)+....=

The ecfentricity of the ellipse ((x-1)^(2))/(2) + (y + (3)/(4)) ^(2)= (1)/(16) is