दिए चित्र में यदि, AB||CD तो सिद्ध कीजिये कि `DeltaAOB~DeltaDOC`

In the given figure, AB||CD and AB=CD , prove that: DeltaAOB~=DeltaDOC

In the adjoining figure, AB = CD and AB||CD prove that (i) DeltaAOB cong DeltaDOC (ii) AD and BC bisect each other at the point O.

In the adjoining figure, AB = CD and AB||CD prove that (i) DeltaAOB cong DeltaDOC (ii) AD and BC bisect each other at the point O.

In the adjoining figure AB = CD and AB"||"CD prove that : (i) DeltaAOB cong DeltaDOG (ii) AD and BC bisect each other at point O.

In the adjoining figure AB = CD and AB"||"CD prove that : (i) DeltaAOB cong DeltaDOG (ii) AD and BC bisect each other at point O.

In the given figure, AB"||"CD and O is the midpoint of AD. Show that (i) DeltaAOB~=DeltaDOC. (ii) O is the midpoint of BC.

In the figure AB || CD, AD and BC intersect at o and O is mid-point of AD. Show that (i) DeltaAOB~=DeltaDOC and (ii) OB=OC .

Line-segment AB is parallel to another line-segment CD. O is the mid-point of AD. Show that (i) DeltaAOB ~= DeltaDOC (ii) O is also the mid-point of BC.

Line-segment AB is parallel to another line-segment CD. O is the mid-point of AD. Show that (i) DeltaAOB ~= DeltaDOC (ii) O is also the mid-point of BC.

Line-segment AB is parallel to another line-segment CD. O is the mid-point of AD. Show that (i) DeltaAOB ~= DeltaDOC (ii) O is also the mid-point of BC.