A particle starts from the origin with a velocity of 10 and moves along a straight line. If its acceleration be `(2t^2-3t) (cm)/s^2` at the end of t seconds, then find its velocity and the distance from the origin at the end of 6 seconds

A particle starts form the origin with a velocity of 10 cm/s and moves along a straight line. If its acceleration be (2t^(2)-3t)cm//s^(2) at the end of t seconds, then fing its velocity and the distance from the origin at the end of 6 seconds.

A particle starts from the origin with a velocity 5 cm/s and moves in a straight line its accelration at time t seconds being (3t^(2)-5t)cm//s^(2) . Find the velocity of the particle and its distance from the origin at the end of 4 seconds.

A particle starts from the origin with a velocity of 2cm/s and moves along a straight line.If the acceleration of the particle at a distance xcm from the origin be (2x-(3)/(2))(cm)/(s^(2)), find the velocity of the particle at a distance 7cm from the origin.

A particle starts from rest at t=0 and moves along a straight line with a variable acceleration given by a (t)=(3t+1)ms^(-2) ,where t],[ is in seconds.The velocity of the particle at t=4s is

A particle starts from the origin and moves along a stright line If the velocity of the particle at time t seconds 10t cm/s then find the distance traversed during fist seconds after the start.

A point moves in a straight line and after t seconds, its accelearation is (2t+1)(cm)/sec^2 . If its velocity is 4cm/sec when t=0, find its velocity after 2 seconds and the distance moved it by in 3 seconds.

A particle starts from the origin and moves along a straight line. If the velocity of the particle at time t seconds be 10t cm/s, find the distance traversed during first 4 seconds after the start.

A particle starts motion from rest and moves along a straight line. Its velocity-time graph is shown. Find out speed of particle at t=2s and at t=3s .

A particle moves in a straight line and its velocity v (in cm/s ) at time t (in second ) is 6t^(2) - 2t^(3) , find its acceleration at the end of 4 seconds.

The acceleration of a particle moving along a straight line is (6t^(2)-3t)cm//s^(2) , at time t seconds. If the velocity of the particel at time 2 seconds be 10cm/s, find its velocity at time t seconds.