If `f(x)= logx and f(1)=0`; show then `f(x)=x(logx-1)+1`.

If f'(x)=logx and f(1)=0, show f(x)=x(logx-1)+1.

f(x)=cos(logx) , then

f(x)=cos(logx) , then

If f(x) = logx, then d/(dx)f(logx) =

If f(x)=log(logx)," then "f'(e)=

If f(x)=|logx| then for x!=1 , then what is f'(x) ?

If f(x)=x^(alpha) logx and f(0)=0 , then the value of alpha for which Roll's theorem can be applied in [0, 1] is :

Column I Column II f(x)=x^2logx f(x) has one point of minima f(x)=x(log)_e x q. f(x) has one point of maxima f(x)=(logx)/x r. f(x) increase x in (0,e) f(x)=x^(-x) s. f(x) decrease x in (0,1/e)

If f(x)=e^(2x).logx,(x gt 0) then find f'(x) .