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0.2 "mole" of NH(4)Cl are introduced int...

`0.2 "mole"` of `NH_(4)Cl` are introduced into an empty container of `10 litre` and heated to `327^(@)C` to attain equilibrium as : `NH_(4)Cl_((s))hArrNH_(3(g))+HCl_((g))`, `(K_(p)=0.36 atm^(2))`.
The quantity of solid `NH_(4)Cl` left is :

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