20 ml of 10 M HCl and 10 ml of `18 M H_2SO_4` are mixed and sufficient water is added to make upto one litre. Calculate the molarity of proton in the mixture.

Explanation

`V_1` = volume of HCl solution = 20 mL
`V_2` = volume of `H_2SO_4` solution = 10 mL
V = volume of mixture = 1000 mL
`N_1` = Normality of HCl solution `= 1 xx M = 10 N`
`N_2` = Normality of `H_2SO_4` solution = `2 xx M = 36 N`
Normality of acid in the mixture, `N = (V_1N_1 + V_2N_2)/(V) = (20 xx 10 + 10 xx 36)/(1000) = 0.56 N `
Molarity of proton `(H^+)` in the mixture = `0.56 mol L^(-1)`.