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The solubility of a substance X at 25^@C...

The solubility of a substance X at `25^@C` and `50^@C` in water is respectively 35 and 50. If 300 grams of saturated solution at `50^@C` is cooled to `25^@C` , calculate the maximum mass of 'X' separated out.

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300 grams of solution at `50^@C = 200g` of solvent +100 g of solute. The solubility of .X. in each 100 g of solvent decreases from 50 g to 35 g from higher temperature `50^@C` to lower `35^@C`.
The mass of .X. may be retained in 200 g solvent at `25^@C = 2 xx 35 = 70g`
Maximum mass of .X. that may be separated = `100 - 70 = 30 g`.
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