Explain Raoult's law for a solution containing non-volatile solute.

The molality of an aqueous dilute solution containing non-volatile solute is 0.1 m. What is the boiling temperature (in .^(@)C ) of solution? (Boiling point elevation constant, k_(b) = 0.52 kg mol^(-1) K boiling temperature of water = 100 .^(@)C )

Relative lowering of a solution containing a non volatile solute (A) in a solvent (B) is 2%. What is the mole percentage of component 'B' in the solution.

Relative lowering of a solution containing a non volatile solute (X) in a solvent (Y) is 3%. What is the mole percentage of component 'Y' in the solution.

State Raoult's law.

Which of the following statements are correct (a) the boiling point of a solution is greater than pure solvent (b) the temperature where the vapour pressure of liquid equals to atmospheric pressure is called its boiling point (c) the vapour pressure of pure solvent is less than the vapour pressure of solution containing non volatile solute. (d) the temperature of liquid remained in the container after evaporation is more than before the evaparation

The vapour pressure of a solution containing non volatile solute is less than the vapour pressure of pure of solvent. Give reason.

Calculate the vapour pressure of a solution containing 10gm of non-volatile solute in 80gm of ethanol of at 298K [The vapour pressure of pure ethanol at 298K is 22.45 mm and Molecular weight of solute is 120]

An aqueous dilute solution containing non-volatile solute boils at 100.052^(@)C . What is the molality of solution? ( K_(b) - 0.52 kg.mol^(-1)K , boiling temperature of water = 100^(@)C )

pH = 0 for a solution. It contains