A column of 0.05 M NaOH solution of diameter 1 cm and length 1m has resistace `1.11 xx 10^(4)` ohm. Calculate the resistivity, conductivity and molar conductivity.

Explanation

Area `a = pi r^2 = (22//7) (0.5 cm)^(2) = 7.85 xx 10^(-5) m^2`
Length = l = 1m
Resistance = `R = 1.11 xx 10^(4)`
Resistivity = `rho = R a/l = (1.11 xx 10^(4) xx 7.85 xx 10^(-5))/(1) = 0.871 Omega m`
Conductivity = `k = rho^(-1) = (0.871 "ohm" m)^(-1) = 1.15 S m^(-1)`
Molar conductivity = `mu = (k xx 1000)/("molarity") = (1.15 xx 1000)/(0.05) = 2.3 xx 10^(4) S m^(2) mol^(-1)`