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The conductivity of 0.1 M KCl solution i...

The conductivity of 0.1 M KCl solution is `1.29 S m^(-1)`. If the resistance of the cell filled with 0.1 M KCl is `100 Omega`, Calculate the cell constant.

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The cell constant filled with electrolytic solution is given as,
Cell constant = specific conductivity `xx` resistance
Cell constant = `1.29 S m^(-1) xx 100 Omega`
`= 1.29 m^(-1) = 129 cm^(-1)`.
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