During the electrolysis of fused potassium chloride at platinum electrodes, 0.25 gram atom of metal is liberated. What would be the volume of chlorine that can be collected in the experiment at STP?

Explanation

Reaction at cathode, `K^(+) + e^(-) to K` and anode, `2Cl^(-) to 2e^(-) + Cl_(2)`
For every one gram atom of potassium liberated, 0.5 mol of chlorine is released.
For 0.25 gram atom of potassium liberated, moles of chlorine released = 0.125.
Volume of chlorine released in the experiment at STP = `0.125xx 22.4 = 2.8 L`.