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The conductivity of 0.001028 mol L^(-1) ...

The conductivity of `0.001028 mol L^(-1)` acetic acid is `4.95 xx 10^(-5) S cm^(-1)`. Calculate its dissociation constant if `Lambda_(m)^(0)` for acetic is `390.5 S cm^(2) mol^(-1)` ?

Text Solution

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The correct Answer is:
`1.75 xx 10^(-5) mol L^(-1)`
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