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Ag^(+) + e^(-) rarr Ag, E^(0) = + 0.8 V ...

`Ag^(+) + e^(-) rarr Ag, E^(0) = + 0.8 V and Zn^(2+) + 2e^(-) rarr Zn, E^(0) = -076 V`. Calculate the cell potential for the reaction, `2Ag + Zn^(2+) rarr Zn + 2Ag^(+)`

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The correct Answer is:
`-1.56 V`
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AAKASH SERIES-ELECTROCHEMISTRY -EXERCISE - 4.2
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  3. The standard potential of Ni^(2+), Ni is -0236 V. It this electrode is...

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  8. E0 values of Zn^(2+), Zn , Mg^(2+), Mg and Cu^(2+), Cu are -0.76 V, ...

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  9. At 298 K the equilibrium constant for the redox reaction CuSO4 + Fe <...

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  10. Ag^(+) + e^(-) rarr Ag, E^(0) = + 0.8 V and Zn^(2+) + 2e^(-) rarr Zn, ...

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  11. E^@ value for Fe^(3+) 3e^(-) to Fe and Fe^(2+) + 2e^(-) to Fe are -0.0...

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  16. At 25^@C potential of the cell, Pt, H2(g), HCl (aq)"//"AgCl(s), Ag(s) ...

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  18. E^(0) = -08275V for the reaction, 2H2O + 2e^(-) to 2OH^(-) + H(2).Calc...

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