`2(sin ^(6) theta+ cos ^(6)theta) -3(sin ^(4) theta+ cos ^(4)theta)=`

sin ^(6) theta+cos ^(6) theta+3 sin ^(2) theta . cos ^(2) theta=

The value of (sin ^(6)theta + cos ^(6) theta + 3sin^(2) theta cos ^(2)theta) is-

Find the value of 6(sin^(6)theta+cos^(6)theta)-9(sin^(4)theta+cos^(4)theta)+4

Prove that: sin^(6) theta + cos^(6) theta =1 - 3 sin^(2) theta cos^(2) theta

4(sin^(6)theta+cos^(6)theta)-6(sin^(4)theta+cos^(4)theta) is equal to

4(sin^(6)theta+cos^(6)theta)-6(sin^(4)theta+cos^(4)theta) is equal to

Find the value of 2(sintheta^(6)+cos^(6)theta)-3(sin^(4)theta+cos^(4)theta)

If sin theta+sin ^(2) theta+sin ^(3) theta=1 then cos ^(6) theta-4 cos ^(4) theta+8 cos ^(2) theta=

The value of 8(sin^(6)theta+cos^(6)theta)-12(sin^(4)theta+cos^(4)theta) is equal to

The value of 3(cos theta-sin theta)^(4)+6(sin theta+cos theta)^(2)+4 sin^(6) theta is where theta in ((pi)/(4),(pi)/(2)) (a) 13-4cos^(4) theta (b) 13-4cos^(6) theta (c) 13-4cos^(6) theta+ 2 sin^(4) theta cos^(2) theta (d) 13-4cos^(4) theta+ 2 sin^(4) theta cos^(2) theta