A man throws a ball vertically upward and it rises through 20 m and returns to his hands. What was the initial velocity (u) of the ball and for how much time (T) it remained in the air `[g = 10 m//s^(2)]`

A ball is thrown vertically upwards. It returns 6 s later. Calculate the initial velocity of the ball. (Take g = 10 "m s"^(-2) )

A man, in a train in uniform motion, throws a ball vertically upwards. Will the ball return to his hand?

A ball thrown vertically upward reached a maximum height of 20 m . What was the velocity of the stone at the instant of throwing up?

A ball thrown vertically upwards with an initial velocity of 1.4 m/s returns in 2s. The total dispalcement of the ball is

A ball of mass 400 gm is dropped from a height of 5 m. A boy on the ground hits the ball vertically upwards with a bat with an average force of 100 newton so that it attains a vertical velocity of 20 m/s. The time for which the ball remains in contact with the bat is (g=10m//s^(2))

A ball thrown vertically upward reached a maximum height of 20m What was the velocity of the stone at the instant of throwing up?

A ball of the mass 400gm is dropped from a height of 5m. A boy on the ground hits the ball vertically upwards with a bat with an average force of 100N so that it attains a vertical height of 20m. The time for which the ball remains in contect with the bat is [ g=10m//s^(-2)]

A ball of mass 50 g is dropped from a height of 20 m. A boy on the ground hits the ball vertically upwards with a bat with an average force of 200 N, so that it attains a vertical height of 45 m. The time for which the ball remains in contact with the bat is [Take g=10m//s^(2)]