For a reaction `nA hArr A_b`, degree of dissociation when A trimerises is

For a reaction nA hArr A_n , degree of dissociation when A trimerises is

For a reaction, 4A hArr 5B degree of dissociation is 10% at a pressure of 2 atm and 300 K.what will be approx degree of dissociation at 0.04 atm pressure and 300 K.

Degree of dissociation of weak electrolyte AB is

For the reaction N_2O_4 harr 2NO_(2(g)) , the degree of dissociation at equilibrium is 0.2 at 1 atm. Then K_p will be

The equilibrium constant, K_(p) for the reaction : A hArr 2B is related to degree of dissociation alpha of A and total pressure P as :

Degree OF dissociation||Extent OF reaction

For the reaction N_(2)O_(4)hArr 2NO_(2(g)), the degree of dissociation of N_(2)O_(4) is 0.2 at 1 atm. Then the K_(p) of 2NO_(2)hArr N_(2)O_(4) is

At temperature T, a compound AB_2(g) dissociation according to the reaction, 2AB _2(g) hArr 2AB(g) +B_2(g) with degree of dissociation, alpha , which is small compared to unity . Deduce the expression for alpha in terms of the equilibrium constant K_p and the total pressure P.

At temperature T, a compound AB_2(g) dissociates according to the reaction 2AB_2(g) hArr 2AB(g) + B_2 (g) with a degree of dissociation x, Which is small compared with unity. Predict the expression for K_p in terms of x and the total pressure P.