Relation between displacement x and time t is `x=2-5t+6t^(2)`, the initial acceleration will be :-

If displacement x at time t is x = sqrt(1+ t^(2)) , then acceleration is

If displacement x at time t is x=sqrt(1+t^(2)) , then acceleration is

If a particle starts moving along x-axis from origin with initial velocity u=2m/s and acceleration 4m//s^(2) the relation between displacement and time is given as x=2t+2t^(2) . Draw the displacement time graph for t ul(gt)0 .

If the displacement at time 't' is x = acost, the acceleration is .......

Function of displacement x and time t is defined by equation x=2t^(3)-3t^(2)-4t+1 . Acceleration will be zero at time

The relation between displacement & time of a body is S = (2t^3- 4t^2 + 3t) unit What will be the acceleration after 3s?

The displacement is given by x = 2t^(2) + t + 5 , the acceleration at t = 5 sec will be-

The displacement is given by x = 2t^(2) +t +5 , the acceleration at t = 2s is

If the displacement of a particle is x=t^(3)-4t^(2)-5t , then the acceleration of particle at t=2 is