The acceleration of a particle moving along a straight line is `(6t^2-3t)` cm/`s^2`, at time t seconds, If the velocity of the particle at time 2 seconds be 10 cm/s,find its veloctiy at time t seconds.

The acceleration of a particle moving along a straight line is (6t^(2)-3t)cm//s^(2) , at time t seconds. If the velocity of the particel at time 2 seconds be 10cm/s, find its velocity at time t seconds.

If the acceleration of a particle at time t seconds be 1.2t^(2)ft//s^(2) and velocity of the particle at time 2 seconds be 2.2 ft/s, then find its velocity at time 5 seconds.

A particle starts from the origin and moves along a straight line. If the velocity of the particle at time t seconds be 10t cm/s, find the distance traversed during first 4 seconds after the start.

Figure shows the velocity time graph of a particle moving along straight line (v is m/s and t is in second). It average velocity in 20 seconds will be: .

Figure shows the velocity time graph of a particle moving along straight line (v is m/s and t is in second). It average velocity in 20 seconds will be: .

A particle moving along a straight line has the relation s =t^2 +3, connecting the distance s described by the particle in time 1. Find the velocity and acceleration of the particle at t=4 seconds.

A particle starts from the origin and moves along a stright line If the velocity of the particle at time t seconds 10t cm/s then find the distance traversed during fist seconds after the start.

The displacement of a particle moving in a straight line, is given by s = 2t^2 + 2t + 4 where s is in metres and t in seconds. The acceleration of the particle is.

The equation of motion of a particle moving along a straight line is s=2t^(3)-9t^(2)+12t , where the units of s and t are cm and second. The acceleration of the particle will be zero after: a) 3/2 seconds b) 2/3 seconds c) 1/2 seconds d) 2 seconds

The speed(v) of a particle moving along a straight line is given by v=(t^(2)+3t-4 where v is in m/s and t in seconds. Find time t at which the particle will momentarily come to rest.