A particle is projected with velocity `V_(0)`along axis x . The deceleration on the particle is proportional to the square of the distance from the origin i.e., `a=omegax^(2).`distance at which the particle stops is

A particle is projected with velocity v_(0) along x - axis. The deceleration on the particle is proportional to the square of the distance from the origin i.e. a=-x^(2) . The distance at which particle stops is -

A particle is projected with velocity v_(0) along x - axis. The deceleration on the particle is proportional to the square of the distance from the origin i.e. a=-x^(2) . The distance at which particle stops is -

The distance travelled by a particle is proportional to the squares of time, then the particle travels with

The distance travelled by a particle is proportional to the squares of time, then the particle travels with

A particle of mass m is projected upword with velocity v=(v_(e))/(2) ( v_(e)) escape of the particle is

A particle is projected on x axis with velocity V. A force is acting on it in opposite direction, which is proportional to square of its position. At what distance from origin the particle will stop (m is mass, k = proportionality constant)

A particle retards from a velocity v_(0) while moving in a straight line. If the magnitude of deceleration is directly proportional to the square loop of the speed of the particle, find its average velocity for the total time of its motion.

A particle starts with speed v_(0) from x = 0 along x - axis with retardation proportional to the square of its displacement. Work done by the force acting on the particle is proportional to