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A straight line through the point (3, -2...

A straight line through the point (3, -2) is inclined at an angle `60^(@)` to the line `sqrt3x+y=1`. If it intersects the X-axis, then its equation will be

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A straight line L through the point (3, -2) is inclined at an angle 60^(@) to the line sqrt(3)x+y=1 . If L also intersects the x-axis, then the equation of L is :

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A straight line L through the point (3,-2) is inclined at an angle 60^@ to the line sqrt(3)x+y=1 If L also intersects the x-axis then the equation of L is

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A straight line L passes through (3,-2) also inclined at an angle 60^@ to the line sqrt(3x)+y=1.If L also intersects the x-axis, then the equation of L is: (A) y+sqrt(3x)+2-3sqrt3=0 (B) y-sqrt(3x)+2+3sqrt3=0 (C) sqrt(3y)-x+3+2sqrt3=0 (D) sqrt(3y)+x-3+2sqrt3=0