Home
Class 11
CHEMISTRY
The concentration of bivalent lead ions ...

The concentration of bivalent lead ions in a sample of polluted of polluted water that aslo contains nitrate ions is determined by adding solid sodium sulphate (M=142) to exactly 500mL water. Calculate the molarity of lead ions if 0.355g is sodium sulphate was nedded for complete precipitation of lead ions as sulphate.

Promotional Banner

Similar Questions

Explore conceptually related problems

The concentration of bivalent lead ions in sample of polluted water that also contains nitrate ions is determined by adding solid sodium sulphate (m=142) to exacty 500mL water. Calculate the molarity of lead ions if 0.355g of solium sulphate was needed for complete precipitation of lead ions as sulphate.

The concentration of bivalent lead ions in sample of polluted water that also contains nitrate ions is determined by adding solid sodium sulphate (m=142) to exacty 500mL water 500mL water. Calculate the molarity of kead ion if 0.355g of solium sulphate was needed for complete precipitation of lead ions as sulphate.

How many moles of ions are present in 250mL of a 4.4M solution of sodium sulphate?

Calculate the number of sulphate ions in 100 mL of 0.001 M H_(2)SO_(4) solution.

When concentrated sulphuric acid is added slowly to a solution of ferrous sulphate containing nitrate ion, a brown colour ring is formed. The compositionn of the ring is

On mixing 45.0 mL of 0.25 M lead nitrate solution with 25.0 mL of 0.10 M chromic sulphate solution, precipitation of lead sulphate are formed? Also calculate the molar concentration of the species left behind solution. Assume the lead sulphate is completely insoluble.