`3x+2(x+2)=20-(2x-5)`

Factorize 5(3x-4y)^(2)-20(2x-y)^(2)

Solve the following equation: ((x^2+12x-20)/(3x-5))=(x^2+8x+12)/(2x+3)

x^2-2x+2=0"( 2)"x^2-3x+3=0x^2-3x+4=0"( 4)"x^2-5x+5=0 A quadratic equation whose roots are cosec20 andsec 0 can be(1) x2-2x+ 2 =0(2) x2-3x + 3 = 0(3) x2-3x+ 4= 0(4) x-5x+5= 0

The HCF of p(x) = 26(6x^(4) - x^(3) - 2x^(2)) and q(x) = 20 (2x^(6) + 3x^(5) + x^(4)) is

(16x^(2)-20x+9)/(8x^(2)+12x+21)=(4x-5)/(2x+3)

Solve: (16x^2-20x+9)/(8x^2+12x+21)=(4x-5)/(2x+3)

Simplify: (x^2-3x+2)(5x-2)-\ (3x^2+4x-5)\ (2x-1)

Simplify: (x^(2)-3x+2)(5x-2)-(3x^(2)+4x-5)(2x-1)

Solve: (x^(2)-2x+5)/(3x^(2)-2x-5)>(1)/(2)