`A+3B harr 2C+D`
For this hypothetical reaction, initial moles of A is twice that of B. If at equilibrium, moles of B and C are equal, the percent of B reacted is `:`

For the reaction A+3B hArr 2C+D initial mole of A is twice that of B . If at equilibrium moles of B and C are equal , then percent of B reacted is

For the reaction A+3B hArr 2C+D initial mole of A is twice that of B . If at equilibrium moles of B and C are equal , then percent of B reacted is

In the following reaction, 3A (g)+B(g) hArr 2C(g) +D(g) , Initial moles of B is double at A . At equilibrium, moles of A and C are equal. Hence % dissociation is :

In the following reaction, 3A (g)+B(g) hArr 2C(g) +D(g) , Initial moles of B is double at A . At equilibrium, moles of A and C are equal. Hence % dissociation is :

For the hypothetical reaction, 2A(s)+B(g) hArr 3C(g) What is the equilibrium expression ?

A+B rarr C+D Initially moles of A and B are equal. At equilibrium, moles of C are three times of A. The equilibrium constant of the reaction will be

A+B rarr C+D Initially moles of A and B are equal. At equilibrium, moles of C are three times of A. The equilibrium constant of the reaction will be

In a closed vessel, the reaction 2A+3BhArr4C+2D is maintained at a constant temperature. Initially the no. of moles of A was twice to that of B and at equilibrium B and D have equals no. of moles. At equilibrium the convert order of no. moles of A, B, C and D are-