A particle moves with a constant acceleration `a=2ms^-2` along a straight line. If it moves with an initial velocity of `5ms^-1`, then obtain an expression for its instantaneous velocity.

A particle moves so that it acceleration is always twice its velocity. If its initial velocity is 0.1 ms^(-1) its velocity after it has gone 0.1 mis :

A car is moving with a constant acceleration and initial velocity 2 ms^(-1) on a straight path. After 10 s it attains the velocity 12 ms^(-1). Then find the distance covered by it in this 10 s.

A particle moves in the x-y plane with constant acceleration of 4 ms^-2 in the direction making an angle of 60^@ with, the x-axis. Initially the particle is at the origin and its velocity is 5 ms^-1 along the x-axis. Find the velocity and the position, of the particle at t = 5sec.

A particle moves in the x-y plane with constant acceleration of 4ms^-2 in the direction making an angle of 60^@ with the x-axis, the particle is at the origin and its velocity is 5 ms^-1 , along the x-axis. Find the velocity and the position of the particle at t=5s.

Velocity of a particle at time t=0 is 2ms^(-1) . A constant acceleration of 2ms^(-2) acts on the particle for 1 second at an angle of 60^(@) with its initial velocity. Find the magnitude of velocity at the end of 1 second .

A particle moves in the x-y plane with constant acceleration of 4 "m.s"^(-2) in the direction making an angle of 60^(@) with the x-axis. Initially, the particle is at the origin and its velocity is 5 "m.s"^(-1) along the x-axis. Find the velocity and the position of the particle at t = 5s.

A particle is moving in a straight line and passes through a point O with a velocity of 6ms^(-1) The particle moves with a constant retardation of 2ms^(-2) for 4 s and there after moves with constant velocity. How long after leaving O does the particle return to O

A particle is moving on a straight line with constant retardation of 1 m//s^(2) . Its initial velocity is 10 m//s .