Home
Class 12
CHEMISTRY
Dry air was passed through bulbs contain...

Dry air was passed through bulbs containing a solution of `40` grams of non electrolytic solute in `360` grams of water, then through bulbs containing pure water at the same temperature and finally through a tube in which pumice moistened with strong `H_(2)SO_(4)` was kept. The water bulbs lost `0.0870` grams and the sulphuric acid tube gained `2.175` grams. Calculate the molecular weight of solute.

Promotional Banner

Similar Questions

Explore conceptually related problems

Dry air is passed through bulbs containing a solution 40 grams of non-electrolytic solute in 360 grams of water, then through bulbs containing pure water at the same temperature and finally through a tube in pumice moistened in with strong H_(2)SO_(4) was kept. The water bulbs lost 0.0870 grams and the sulphuric acid tube gained 2.175 grams. Calculate the molecular weight of solute.

Dry air was drawn through bulbs containing a solution of 40 grams of urea in 300 gram of water, then through bulbs containing pure water at the same temperature and finally through a tube in which pumice moistened with strong. H_(2)SO_(4) was kept. The water bulbs lost 0.0870 grams and the sulphide acid tube gained 2.036 grams. Calculate the molecular weight of urea.

A current of dry air was bubbled through in a bulb containing 26.66g of a n organic substance in 200gms of water, then through a bulb at the same temperature containing pure water and finally through a tube containing fused calcium chloride. The loss in weight of water bulb is 0.0870 gms and gain in weight of CaCl_(2) tube is 2.036 gm. Calculate the molecular weight of the organic substance in the solution.

A stream of dry air was passed through a bulb containing a solution of 7.5 g of a compound dissolved in 75 g of water and then through another bulb containing pure water. The loss of mass in the first bulb was 2.81 g and in the second bulb was 0.054 g. Calculate the molecular mass of the compound.

In Ostwald and Walker's appratus, dry air is passed through a solution containing 20 gram of an organic non-volatile solute in 250 ml of water. Then the air was passed through pure water and then through a U-tube containing anhydroous CaCl_(2) . The mass lost in solution is 26 gram and the mass gained in the U-tube is 26.48 gram. Calculate the molecular mass of organic solute.

In Ostwald and Walker's appratus, dry air is passed through a solution containing 20 gram of an organic non-volatile solute in 250 ml of water. Then the air was passed through pure water and then through a U-tube containing anhydroous CaCl_(2) . The mass lost in solution is 26 gram and the mass gained in the U-tube is 26.48 gram. Calculate the molecular mass of organic solute.