As shown in the figure, a disc of mass m is rolling without slipping with angular velocity `omega`. When it crosses point B disc will be in

A circular disc of mass 0.41 kg and radius 10 m rolls without slipping with a velocity of 2 m/s. The total kinetic energy of disc is

A circular disc of mass 0.41 kg and radius 10 m rolls without slipping with a velocity of 2 m/s. The total kinetic energy of disc is

A disc is rolling without slipping with angular velocity omega . P and Q are two points equidistant from the centre C. the order of magnitude fo velocity is

A disc is rolling without slipping with angular velocity omega . P and Q are two points equidistant from the centre C. the order of magnitude fo velocity is

A disc of mass m and radius R is rolling without slipping as shown in the figure. The magnitude of net velocity of the point P is (OP = R/2)

A circular disc of mass 2 kg and radius 10 cm rolls without slipping with a speed 2 m/s. The total kinetic energy of disc is

A circular disc of mass 2 kg and radius 10 cm rolls without slipping with a speed 2 m/s. The total kinetic energy of disc is

A circular disc of mass m and radius r is rolling over a horizontal table top with angular velocity omega . Prove that the total energy of the disc , K = (3)/(4) m omega ^(2) r^(2) .