5 girls and 10 boys sit at random in a row having 15 shairs numbered as 1 to 15. Find the probability that end seats are occupied by the girls and between any two girls odd numbers of boys sit.

5 girls and 10 boys sit at random in a row having 15 chairs numbered as 1 to 15. Find the probability that end seats are occupied by the girls and between any two girls odd numbers of boys sit.

5 girls and 10 boys sit at random in a row having 15 chairs numbered as 1 to 15. Find the probability that end seats are occupied by the girls and between only two girls odd number of boys sit.

5 girls and 10 boys sit at random in a row having 15 chairs numbered as 1 to 15. If the probability that the end seats are occupied by the girls and between any two girls odd number of boys take seat is (20)/(n) , then n is equal to

In how many ways 5 girls and 10 boys can be arranged along a row having 15 chairs numbered 1 to 15 such that the end seats are occupied by the girls and between any girls odd number of boys must be seated.

5 girls and 10 boys sit at random in a row having 15 chairs numbered as 1 to 15, then the number of ways n which they cansit so that end seats are occupoied by the girls and between any two girls odd number of boys sit ils (A) 20xx10!xx5! (B) 15xx10! (C) 25xx1!5! (D) 5xx10

7 boys and 8 girls have to sit in a row on 15 chairs numbered from 1 to 15, then

Find the number of ways in which 10 girls and 90 boys can sit in a row having 100 chairs such that no girls sit at then either end of the rwo and between any two girls, at least five boys sit.

Find the number of ways in which 10 girls and 90 boys can sit in a row having 100 chairs such that no girls sit at then either end of the rwo and between any two girls, at least five boys sit.

4 boys and 4 girls are arranged in a row at random. Find the probability that the boys and girls sit alternatively.

Six boys and six girls sit in a row at random. Find the probability that : the boys and girls sit alternately.