Home
Class 11
CHEMISTRY
For the equilibrium, SrCl(2).6H(2)O(s) ...

For the equilibrium, `SrCl_(2).6H_(2)O(s) hArr SrCl_(2).2H_(2)O(s)+4H_(2)O(g)` the equilibrium constant `K_(P)=16xx10^(-12)"atm"^(4)` at `1^(@)C`.If one litre of air saturated with water vapour at `1^(@)C` is exposed to a large quantity of `SrCl_(2).2H_(2)O(s)`, what weight of water vapour will be absorbed? Saturated vapour pressure of water at `1^(@)C=7.6` torr.

Promotional Banner

Similar Questions

Explore conceptually related problems

For the equilibrium H_(2) O (1) hArr H_(2) O (g) at 1 atm 298 K

SrC_(2)O_(4)darr+2HCl to SrCl_(2)+H_(2)C_(2)O_(4)

The equilibrium constant for the reaction CaSO_(4).5H_(2)H_(2)O(s)hArr CaSO_(4).3H_(2)O(s)+2H_(2)O(g) is equal to

Write the equilibrium constant of the reaction C(s)+H_(2)O(g)hArrCO(g)+H_(2)(g)

For equilibrium ZnSO_(4).7H_(2)O(s)hArrZnSO_(4).2H_(2)O(s)+5H_(2)O(g) K_(P)=56.25xx10^(-10) atm^(5) and vapour pressure of water is 22.8 torr at 298K.ZnSO_(4).7H_(2)O(s) is efflorescent (lose water) when relative humidity is [5sqrt56.25=2.23]

For the equilibrium CuSO_(4)xx5H_(2)O(s)hArrCuSO_(4)xx3H_(2)O(s) + 2H_(2)O(g) K_(p) = 2.25xx10^(-4)atm^(2) and vapour pressure of water is 22.8 torr at 298 K. CuSO_(4) . 5H_(2)O(s) is efflorescent (i.e., losses water) when relative humidity is :