Three identical cells, each of emf 2 V and internal resistance `0.2Omega` are connected in series to an external resistor of `7.4Omega`. Calculate the current in the circuit.

4 cells each of emf 2 V and internal resistance of 1Omega are connected in parallel to a load resistor of 2Omega . Then the current through the load resistor is

24 cells, each of emf 1.5V and internal resistance is 2Omega connected to 12Omega series external resistance. Then,

24 cells, each of emf 1.5V and internal resistance is 2Omega connected to 12Omega series external resistance. Then,

Three identical cells of emf 2 V and internal resistances 0.20 Omega are connected in series. The combination is further connected to an external resistor of 6 Omega . Calculate the current through 6 Omega resistor.

Two cells , one of emf 1.2 V and internal resistance 0.5Omega the other of emf 2 V and internal resiatnce 0.1Omega are connnected in series with an external resistance of 5Omega . What is the current through this resistor ?

Three identical cells each of emf 2 V and internal resistance 1 Omega are connected in series to form a battery. The battery is then connected to a parallel combination of two identical resistors, each of resistance 6 Omega Find the current delivered by the battery.

5 cells each of e.m.f 1.5 V and internal resistance 0.1 Omega are connected in such a manner that the current in an external resistor of 10 Omega is maximum. Draw the circuit diagram of the combination and calculate the current in the circuit.