`(9^6+1)` when divided by 8, would leave a remainder of 0 (b) 1 (c) 2 (d) 3

9^(6)-11 when divided by 8 would leave a remainder of:

(7^75-1) when divided by 8 would leave a remainder of:

9^50+1 When divided by 10 would leave a remainder of:

(27^27+1) when divided by 26 would leave a remainder of:

For an integer n , n !=(n-1)(n-2) .3.2.1. Then, 1!+2!+3!+ 100 ! when divided by 5 leaves remainder 0 (b) 1 (c) 2 (d) 3

3^(2n)+9n+1 when divided by 9 will leave the remainder

The least number which when divided by 5,6,7 and 8 leaves a remainder 3, but when divided by 9 leaves no remainder,is (a) 1677 (b) 1683 (c) 2523 (d) 3363

When the square of any odd number, greater than 1, is divided by 8, it always leaves remainder (a) 1 (b) 6 (c) 8 (d) Cannot be determined

When the square of any odd number, greater than 1, is divided by 8, it always leaves remainder (a)1 (b) 6 (c) 8 (d) Cannot be determined