The total length of a sonometer wire fixed between two bridges is 110 cm. Now, two more bridges are placed to divide the length of the wire in the ratio `6:3:2`. If the tension in the wire is 400 N and the mass per unit length of the wire is `"0.01 kg m"^(-1)`, then the minimum common frequency with which all the three parts can vibrate, is

The total length of a sonometer wire between fixed ends is 110 cm. Two bridges are placed to divide the length of wire in ratio 6:3:2. The tension in the wire is 400 N and the mass per unit length is 0.01 kg/m. What is the minimum common frequency with which three parts can vibrate?

The length of a sonometer wire between two fixed ends is 110cm. Where should the two bridges the placed so as to divide the wire into three segments, whose fundamental frequencies are in the ration 1:2:3?

The total length of a sonometer wire between fixed ends is 110 cm. To bridges are placed to divide the length of the wire in ratio 6 : 3 : 2. What is the minimum common frequency with which three parts can vibrate? Also calculate the ratio of number of loops formed in three parts. The tension in the wire is 400 N and the mass per unit length is 0.01 kg//m .

The length of a sonometer wire is 1m. Where should be the bridge placed to divide the wire into 2 segments, whose fundamental frequencies are in the ratio 1: 2 ?

The length of a sonometer wire AB is 110 cm. Where should the two bridges be placed from A to divide the wire in 3 segments whose fundamental frequencies are in the ratio of 1: 2 : 3 ?

The length of a sonometer wire AB is 100 cm, where should the two bridges be placed from A to divide the wire in 3 segments whose fundamental frequencies are in the ratio of 1:2:6

The length of a sonometer wire AB is 100 cm, where should the two bridges be placed from A to divide the wire in 3 segments whose fundamental frequencies are in the ratio of 1:2:6