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In a DeltaABC, 2ac sin((A-B+C)/2) is equ...

In a `DeltaABC, 2ac sin((A-B+C)/2)` is equal to (a) `a^2+b^2-c^2` (b) `c^2+a^2-b^2` (c) `b^2-c^2-a^2` (d) `c^2-a^2-b^2`

A

`a^(2)+b^(2)-c^(2)`

B

`c^(2)+a^(2)-b^(2)`

C

`b^(2)-a^(2)-c^(2)`

D

`c^(2)-a^(2)-b^(2)`

Text Solution

Verified by Experts

The correct Answer is:
b
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