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If in aDeltaABC,sinA,sinb,sinC are in A...

If in `aDeltaABC,sinA,sinb,sinC` are in A.P ., then

A

the altitudes are in A.P

B

the altitudes are in H.P.

C

the angles are in A.P.

D

the angles are in H.P

Text Solution

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The correct Answer is:
To solve the problem step by step, we need to establish that if \( \sin A, \sin B, \sin C \) are in arithmetic progression (A.P.), then the altitudes from vertices A, B, and C of triangle ABC will be in harmonic progression (H.P.). ### Step-by-Step Solution: 1. **Understanding the Given Condition**: - We are given that \( \sin A, \sin B, \sin C \) are in A.P. This means: \[ 2 \sin B = \sin A + \sin C \] 2. **Using the Area of the Triangle**: - The area \( \Delta \) of triangle ABC can be expressed in terms of its sides and corresponding altitudes: \[ \Delta = \frac{1}{2} \times a \times P_1 = \frac{1}{2} \times b \times P_2 = \frac{1}{2} \times c \times P_3 \] - Here, \( P_1, P_2, P_3 \) are the altitudes from vertices A, B, and C respectively. 3. **Expressing Altitudes in Terms of Area**: - From the area expressions, we can derive the altitudes: \[ P_1 = \frac{2\Delta}{a}, \quad P_2 = \frac{2\Delta}{b}, \quad P_3 = \frac{2\Delta}{c} \] 4. **Using the Sine Rule**: - According to the sine rule: \[ \frac{a}{\sin A} = \frac{b}{\sin B} = \frac{c}{\sin C} = k \quad \text{(some constant)} \] - Thus, we can express the sides in terms of the sine values: \[ a = k \sin A, \quad b = k \sin B, \quad c = k \sin C \] 5. **Substituting into Altitude Formulas**: - Substitute \( a, b, c \) in the altitude formulas: \[ P_1 = \frac{2\Delta}{k \sin A}, \quad P_2 = \frac{2\Delta}{k \sin B}, \quad P_3 = \frac{2\Delta}{k \sin C} \] 6. **Relating the Altitudes**: - We can express the altitudes as: \[ P_1 = \frac{2\Delta}{k \sin A}, \quad P_2 = \frac{2\Delta}{k \sin B}, \quad P_3 = \frac{2\Delta}{k \sin C} \] 7. **Finding the Relationship**: - Since \( \sin A, \sin B, \sin C \) are in A.P., we know that: \[ \frac{1}{\sin A}, \frac{1}{\sin B}, \frac{1}{\sin C} \] - will be in H.P. (Harmonic Progression). 8. **Conclusion**: - Therefore, since the reciprocals of the sines are in H.P., it follows that the altitudes \( P_1, P_2, P_3 \) are also in H.P. ### Final Answer: The altitudes \( P_1, P_2, P_3 \) from vertices A, B, and C of triangle ABC are in harmonic progression (H.P.). ---
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