Home
Class 12
MATHS
One of the diameters of the circle x^2+y...

One of the diameters of the circle `x^2+y^2-12x+4y+6=0` is given by

A

`x+y=0`

B

`x+3y=0`

C

`x=y`

D

`3x+2y=0`

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Topper's Solved these Questions

  • CIRCLES

    MTG-WBJEE|Exercise WB JEE WORKOUT (CATEGORY 2 : Single Option Correct Type)|15 Videos

  • CIRCLES

    MTG-WBJEE|Exercise WB JEE WORKOUT (CATEGORY 3 : One or More One Option Correct Type)|10 Videos

  • BINOMIAL THEOREM

    MTG-WBJEE|Exercise WB JEE Previous Years Questions ( CATEGORY 1 : Single Option Correct Type (1 Mark))|13 Videos

  • COMPLEX NUMBERS

    MTG-WBJEE|Exercise WB JEE Previous Years Questions (CATEGORY 3 : One or More than One Option Correct Type (2 Marks) )|3 Videos

Similar Questions

Explore conceptually related problems

One of the diameter of the circle x^(2)+y^(2)-2x+4y-4=0 , is

If one of the diameters of the circle x^(2)+y^(2)-2x-6y+6=0 is a chord to the circle with center (2,1) ,then the radius of the circle is

If one of the diameters of the circle x^(2)+y^(2)-2x-6y+6=0 is a chord to the circle with centre (2,1), then the radius of circle is:

If (4, 1) be an end of a diameter of the circle x^2 + y^2 - 2x + 6y-15=0 , find the coordinates of the other end of the diameter.

The length of the diameter of the circle x^(2)+y^(2)-4x-6y+4=0 is -

If (1,2)(2,a) are extremities of a diameter of the circle x^(2)+y^(2)-3x-4y+6=0 then a=

The radius of circle x^2+y^2-6x+4y-12=0 is

If one end of a diameter of the circle 3x^(2)+3y^(2)-9x+6y+5=0 is (1,2), then the other end is