Home
Class 12
MATHS
The straight line x+y-1=0 meets the circ...

The straight line `x+y-1=0` meets the circle . `x^2 +y^2-6x-8y=0` at A and B. Then, the equation of : the circle of which AB is a diameter, is

A

`x^(2)+y^(2)-2y-6=0`

B

`x^(2)+y^(2)+2y-6=0`

C

`2(x^(2)+y^(2))+2y-6=0`

D

`3(x^(2)+y^(2))+2y-6=0`

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Topper's Solved these Questions

  • CIRCLES

    MTG-WBJEE|Exercise WB JEE WORKOUT (CATEGORY 2 : Single Option Correct Type)|15 Videos
  • CIRCLES

    MTG-WBJEE|Exercise WB JEE WORKOUT (CATEGORY 3 : One or More One Option Correct Type)|10 Videos
  • BINOMIAL THEOREM

    MTG-WBJEE|Exercise WB JEE Previous Years Questions ( CATEGORY 1 : Single Option Correct Type (1 Mark))|13 Videos
  • COMPLEX NUMBERS

    MTG-WBJEE|Exercise WB JEE Previous Years Questions (CATEGORY 3 : One or More than One Option Correct Type (2 Marks) )|3 Videos

Similar Questions

Explore conceptually related problems

If line y= 2x meets circle x^(2) + y^(2) - 4x = 0 in point A and B , then equation of circle of which AB is diameter is

If line y = 4x meets circle x^(2) + y^(2) - 17 x = 0 in points A and B , then equation of circle of which AB is a diameter is

The line 2x-y+6=0 meets the circle x^(2)+y^(2)-2y-9=0 at A and B. Find the equation of the circle on AB as diameter.

If x-y+1=0 meets thwe cicle x^(2)+y^(2)+y-1=0 at a and b, then the equation of the circle with ab as diameter, is

The circle x^(2)+y^(2)=4 cuts the circle x^(2)+y^(2)+2x+3y-5=0 in A and B ,Then the equation of the circle on AB as diameter is

The circle x^(2)+y^(2)=4 cuts the circle x^(2)+y^(2)+2x+3y-5=0 in A &B. Then the equation of the circle on AB as a diameter is:

If the circle x^(2)+y^(2)+3x+2y+1=0 cuts another circles x^(2)+y^(2)+3x+4y+2=0 in A and B ,then the equation of the circle with AB as a diameter is