Home
Class 12
MATHS
The intercept on the line y=x by the cir...

The intercept on the line `y=x` by the circle `x^2+y^2-2x=0` is AB. Equation of the circle with AB as a diameter is (A) `(x-1/2)^3+(y-1/2)^2=1/2` (B) `(x-1/2)^2+(y-1/2)^2=1/4` (C) `(x+1/2)^2+(y+1/2)^2=1/2` (D) `(x+1/2)^2+(y+1/2)^2=1/4`

A

`x^(2)+y^(2)=1`

B

`x(x-1)+y(y-1)=0`

C

`x^(2)+y^(2)=2`

D

`(x-1)(x-2)+(y-1)(y-2)=0`

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Topper's Solved these Questions

  • CIRCLES

    MTG-WBJEE|Exercise WB JEE WORKOUT (CATEGORY 2 : Single Option Correct Type)|15 Videos

  • CIRCLES

    MTG-WBJEE|Exercise WB JEE WORKOUT (CATEGORY 3 : One or More One Option Correct Type)|10 Videos

  • BINOMIAL THEOREM

    MTG-WBJEE|Exercise WB JEE Previous Years Questions ( CATEGORY 1 : Single Option Correct Type (1 Mark))|13 Videos

  • COMPLEX NUMBERS

    MTG-WBJEE|Exercise WB JEE Previous Years Questions (CATEGORY 3 : One or More than One Option Correct Type (2 Marks) )|3 Videos

Similar Questions

Explore conceptually related problems

If x-y+1=0 meets thwe cicle x^(2)+y^(2)+y-1=0 at a and b, then the equation of the circle with ab as diameter, is

Find the equation of the tangent and normal to the circle 2x^2+2y^2-3x-4y+1=0 at the point (1,2)

The tangents to the circle x^(2)+y^(2)-4x+2y+k=0 at (1,1) is x-2y+1=0 then k=

The equation of the curve passing through origin, whose slope at any point is (x(1+y))/(1+x^2) , is (A) (1+y)^2-x^2=1 (B) x^2+(y+1)^2=1 (C) (x+y)y=1-x^2 (D) x=ye^((1+y))

If the circle x^(2)+y^(2)+2x+3y+1=0 cuts x^(2)+y^(2)+4x+3y+2=0 at A and B ,then find the equation of the circle on AB as diameter.

The length of the common chord of the circles x^(2)+y^(2)-2x-1=0 and x^(2)+y^(2)+4y-1=0 , is

Find the equation of the circle whose diameter is the common chord of the circles x^(2) + y^(2) + 2x + 3y + 1 = 0 and x^(2) + y^(2) + 4x + 3y + 2 = 0

The line lambda x+mu y=1 is a normal to the circle 2x^(2)+2y^(2)-5x+6y-1=0 if