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The coordinates of the vertex of the par...

The coordinates of the vertex of the parabola `y^(2)=4(x+y)` is

A

(0,0)

B

(2,1)

C

(-1,2)

D

(1,2)

Text Solution

AI Generated Solution

The correct Answer is:
To find the coordinates of the vertex of the parabola given by the equation \( y^2 = 4(x + y) \), we will follow these steps: ### Step 1: Rewrite the equation Start with the given equation: \[ y^2 = 4(x + y) \] Rearranging it gives: \[ y^2 - 4y = 4x \] ### Step 2: Complete the square for \( y \) To complete the square for the left-hand side, we take the coefficient of \( y \), which is \(-4\), halve it to get \(-2\), and then square it to get \(4\). We add and subtract \(4\) on the left side: \[ y^2 - 4y + 4 - 4 = 4x \] This simplifies to: \[ (y - 2)^2 - 4 = 4x \] Now, add \(4\) to both sides: \[ (y - 2)^2 = 4x + 4 \] ### Step 3: Factor the right-hand side Factor the right-hand side: \[ (y - 2)^2 = 4(x + 1) \] ### Step 4: Identify the vertex The equation is now in the standard form of a parabola: \[ (y - k)^2 = 4a(x - h) \] where \( (h, k) \) is the vertex. From our equation, we can identify: - \( k = 2 \) - \( h = -1 \) Thus, the coordinates of the vertex are: \[ (h, k) = (-1, 2) \] ### Final Answer The coordinates of the vertex of the parabola are \((-1, 2)\). ---
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