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For what values of x the function f(x)=x...

For what values of `x` the function f(x)=`x^(4)-4x^(3)+4x^(2)+40` is monotonically increasing ?

A

`0 lt x lt 1`

B

`1 lt x lt 2`

C

`2 lt x lt 3`

D

`4 lt x lt 5`

Text Solution

AI Generated Solution

The correct Answer is:
To determine the values of \( x \) for which the function \( f(x) = x^4 - 4x^3 + 4x^2 + 40 \) is monotonically increasing, we need to follow these steps: ### Step 1: Find the derivative of the function To find when the function is increasing, we first need to compute its derivative \( f'(x) \). \[ f'(x) = \frac{d}{dx}(x^4 - 4x^3 + 4x^2 + 40) \] Using the power rule, we differentiate each term: \[ f'(x) = 4x^3 - 12x^2 + 8x \] ### Step 2: Set the derivative greater than zero The function \( f(x) \) is monotonically increasing when \( f'(x) > 0 \). \[ 4x^3 - 12x^2 + 8x > 0 \] ### Step 3: Factor the derivative We can factor out the common term \( 4x \): \[ 4x(x^2 - 3x + 2) > 0 \] Now, we can factor the quadratic expression: \[ x^2 - 3x + 2 = (x - 1)(x - 2) \] So, we rewrite the inequality: \[ 4x(x - 1)(x - 2) > 0 \] ### Step 4: Identify critical points The critical points occur when \( f'(x) = 0 \): \[ 4x(x - 1)(x - 2) = 0 \] This gives us the critical points: \[ x = 0, \quad x = 1, \quad x = 2 \] ### Step 5: Test intervals We will test the intervals determined by the critical points: \( (-\infty, 0) \), \( (0, 1) \), \( (1, 2) \), and \( (2, \infty) \). 1. **Interval \( (-\infty, 0) \)**: Choose \( x = -1 \) \[ f'(-1) = 4(-1)((-1) - 1)((-1) - 2) = 4(-1)(-2)(-3) < 0 \] (Decreasing) 2. **Interval \( (0, 1) \)**: Choose \( x = 0.5 \) \[ f'(0.5) = 4(0.5)((0.5) - 1)((0.5) - 2) = 4(0.5)(-0.5)(-1.5) > 0 \] (Increasing) 3. **Interval \( (1, 2) \)**: Choose \( x = 1.5 \) \[ f'(1.5) = 4(1.5)((1.5) - 1)((1.5) - 2) = 4(1.5)(0.5)(-0.5) < 0 \] (Decreasing) 4. **Interval \( (2, \infty) \)**: Choose \( x = 3 \) \[ f'(3) = 4(3)((3) - 1)((3) - 2) = 4(3)(2)(1) > 0 \] (Increasing) ### Step 6: Conclusion The function \( f(x) \) is monotonically increasing in the intervals \( (0, 1) \) and \( (2, \infty) \). Thus, the values of \( x \) for which the function is monotonically increasing are: \[ x \in (0, 1) \cup (2, \infty) \]
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