Home
Class 12
MATHS
The normal to the curve y=x^2-x+1 drawn ...

The normal to the curve `y=x^2-x+1` drawn at the points with the abscissa `x_1=0,x_2=-1` and `x_3=5/2`

A

are parallel to each other

B

are pair wise perpendicular

C

are concurrent

D

are not concurrent

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Topper's Solved these Questions

  • APPLICATION OF DERIVATIVES

    MTG-WBJEE|Exercise WB JEE Previous Years Questions ( CATEGORY 3 : One or More than One Option Correct Type (2 Marks) )|11 Videos

  • APPLICATION OF DERIVATIVES

    MTG-WBJEE|Exercise WB JEE Previous Years Questions ( CATEGORY 1: Single Option correct Type (1 Mark))|15 Videos

  • A.P.,G.P.,H.P.

    MTG-WBJEE|Exercise WB JEE Previous Years Questions ( CATEGORY 2 : Single Option Correct Type (2 Mark ) )|5 Videos

  • APPLICATION OF INTEGRALS

    MTG-WBJEE|Exercise WE JEE PREVIOUS YEARS QUESTIONS (CATEGORY 3 : ONE OR MORE THAN ONE OPTION CORRECT TYPE)|3 Videos

Similar Questions

Explore conceptually related problems

The equation of the normal to the curve y=x(2-x) at the point (2, 0) is

The equation of normal to the curve y=x^(3)-x^(2)-1 at the point whose abscissa is -2, is

The equation of normal to the curve y=x^2-2x+1 at (0,1) is

Find the equation of the normal to the curve x^(2)+2y^(2)-4x-6y+8=0 at the point whose abscissa is 2 .

The equation of normal to the curve y= x ^(2) + 2 at point (1,1) is :

Equation of normal to the curve y^(2)=(x)/(2-x) at the point (1,1) is

The y-intercept of the line normal to the curve y^2=x^2+33(y gt 0) at the point with abscissa 4 is :

Equation of the normal to the curve y=-sqrt(x)+2 at the point (1,1)

The equation of the normal to the curve y=e^(-2|x|) at the point where the curve cuts the line x = 1//2 is