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Five moles of hydrogen (gamma = 7//5), i...

Five moles of hydrogen `(gamma = 7//5)`, initially at `STP`, is compressed adiabatically so that its temperature becomes `400^(@)C`. The increase in the internal energy of the gas in kilojules is `(R = 8.30 J//mol-K)`

A

`21.55`

B

`41.50`

C

`65.55`

D

`80.55`

Text Solution

Verified by Experts

The correct Answer is:
b
`C_(p)/C_(V) = gamma = 7/5 ` and no. of moles , `mu = 5 `.
` :. " Work done " = (mu R)/ (gamma - 1) xx Delta T = (8.3 xx 400 xx 5)/(7/5 - 1) = 41.5 kJ `
Now, work done = change in internal energy
(`. :. Delta Q = 0 ` for adiabatic process)
Therefore , change in internal energy ` = 41.5 ` kJ.
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