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A gas under constant pressure of 4.5 xx ...

A gas under constant pressure of `4.5 xx 10^(5) Pa` when subjected to `800 kJ` of heat, changes the volume from `0.5 m^(3) to 2.0 m^(3)`. The change in internal energy of the gas is

A

`6.75 xx 10^(5) J`

B

`5.25 xx 10^(5) ` J

C

`3. 25 xx 10^(5) J`

D

`1. 25 xx 10^(5) J ` .

Text Solution

Verified by Experts

The correct Answer is:
d
Given, `P = 4.5 xx 10^(5) Pa, dQ = 800 kJ V_(1) = 0.5 m^(3) , V_(2) = 2 m^(3)`
`dW = P(V_(2) - V_(1)) = 4.5 xx 10^(5) (2 - 0.5) = 6.75 xx 10^(5) J`
Change in internal energy
`dU = dQ - dW = 800 xx 10^(3) - 6.75 xx 10^(5) `
` = 1.25 xx 10^(5) J `
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