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One mole of an ideal gas requires 207 J ...

One mole of an ideal gas requires 207 J heat to raise its temperature by 10 K when heated at constant pressure. If the same gas is heated at constant volume to raise the temperature by the same 10 K, the heat required will be (R, the gas constant = `8.3 JK^(-1) mol^(-1)`):

A

`198.7 ` J

B

`29 J`

C

`215.3 J`

D

`124 J`

Text Solution

Verified by Experts

The correct Answer is:
d
Using `C_(p) - C_(V) = R `, (Mayer.s formula)
` C_(p)` is heat needed for raising temperature by 1 K.
` :. C_(p) = 20.7 "J/mol" ^(@) C`
Given `R = 8.3 ` J/mol K
` :. C_(V) = 20.7 - 8.3 = 12.4 "J/mol" ^(@) C`
` :. ` For raising by `10 K = 124 J`.
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