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One mole of an ideal gas at temperature ...

One mole of an ideal gas at temperature `T_(1)` expands according to the law (P/V) = constant. Find the work done when the final temperature becomes `T_(2)`.

A

`R(T_(2) - T_(1))`

B

`(R//2)(T_(2) - T_(1))`

C

`(R//4)(T_(2) - T_(1))`

D

`PV(T_(2) - T_(1))`

Text Solution

Verified by Experts

The correct Answer is:
b

Work done,
`W = underset(V_(1))overset(V_(2))int PdV = underset(V_(1))overset(V_(2))int KVdV (.:. P/V = K = "constant")`
` :. W = 1/2 K(V_(2)^(2) - V_(1)^(2))`
As we know, in case of an ideal gas,
`PV = RT . " But " P = KV` ,
` :. KV^(2) = RT " or " K(V_(2)^(2) - V_(1)^(2)) = R (T_(2) - T_(1))`
` :. W = R/2 (T_(2) - T_(1))`
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