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One mole of an ideal monoatomic gas is h...

One mole of an ideal monoatomic gas is heated at a constant pressure of one atmosphere from`0^(@)` to `100^(@)C.` Then the change in the internal energy is

A

`0.83 xx 10^(3) J`

B

`4.6 xx 10^(3) J`

C

`2.08 xx 10^(3) J`

D

`1.25 xx 10^(3) J`

Text Solution

Verified by Experts

The correct Answer is:
d
Here, `R = 8.32 J mol^(-1) K^(-1)`
`Delta T = 100^(@) C - 0^(@) C = 100^(@) C, n = 1`
At constant pressure,
`Delta Q = nX_(p) Delta T " and " Delta W = n R Delta T `
According to first law of thermodynamics,
`Delta Q = Delta U + Delta W`
`Delta U = Delta Q - Delta W = n C_(p) Delta T - n R Delta T`
` = n Delta T (C_(p) - R) = n C_(v) Delta T " " (. :. C_(p) - C_(v) = R) `
For monoatomic gas, `C_(V) = 3/2 R`
` :. Delta U = 1 xx 3/2 xx 8.32 xx 100 = 1.25 xx 10^(3) J`
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