Two very long, straight, parallel wires carry steady currents `I` and `-I` respectively.The distance between the wires is `d`.At a certain instant of time, a point charge `q` is at a point equidistant from the two wires,in the plane of wires.Its instantaneous velocity `vecv` is perpendicular to this plane.The magnitude of the force due to the magnetic field acting on the charge at this instant is:

Options

A. `(mu_(0)Iqv)/(2pi d)`
B. `(mu_(0)I qv)/(pi d)`
C. `(2mu_(0)Iqv)/(pi d)`
D. 0

Answer

D

Explanation

The angle between magnetic field produced by the wires and velocity of the charge particle will be zero, and due to this the force will be,
`F= qv B sin 0^(@)= 0`