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A conducting rod of 1 m length and 1 kg ...

A conducting rod of 1 m length and 1 kg mass is suspended by two verticle wires through its ends. An external magnetic field of 2T is applied normal to the rod. Now the current to be passed through the rod so as to make the tension in the wire zero is
[Take `g = 10 ms^(-2)]`

A

0.5A

B

15A

C

5A

D

1.5A

Text Solution

Verified by Experts

The correct Answer is:
C
Magnetic force on rod= Bil and weight of the rod= mg
For on tension in wire, Bil= mg or `I= (mg)/(Bl) = (1 xx 10)/(2 xx 1)= 5A`
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