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A man wishes to estimate the distance of...

A man wishes to estimate the distance of a nearby tower from him. He stands at a point A in front of the tower C and spots a very distant object O in line with AC. He then walks perpendicualr to AC upto B, a distaance of 100m and looks at O and C again. Since O is very distant, the direction of BO is practically the same as AO, but he finds the line of sight of C shifted from the original line of sight by an angle `theta = 40^@ ( theta "is known as parallax").` Estimate the distance fo the tower C from his original position A.

Text Solution

Verified by Experts

We have, parallax angle `theta = 40^(@)` From fig.2.3. AB=AC tan`theta`
AC=AB/tan`theta` = 100m/tan`40^(@) = 100m//0.8391 = 119`
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