At a hydroelectric power plant, the water pressure head is at a height of 300 m and the water flow available is `100 m^(3) s^(-1)`. If the turbine generator efficiency is 60%, estimate the electric power available from the plant `(g = 9.8 ms^(-2))`.

Explanation

Hydroelectric power `=h rho g xx A xx v = h rho g beta`
where `beta=Av` is the flow (volume of water flowing per second across a cross-section).
Electric power available `=0.6xx300xx10^(3)xx9.8xx100W`
`=176MW`